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Question

Consider the following changes.
M(s)M(g) .....(i)
M(s)M2+(g)+2e .....(ii)
M(g)M+(g)+e. .....(iii)
M+(g)M2+(g)+e. .....(iv)
M(g)M2+(g)+2e .....(v)
The second ionization energy of M can be calculated from the energy values associated with:

A
1+3+4
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B
21+3
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C
1+5
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D
53
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Solution

The correct option is A 53
Second ionization energy is amount of energy required to take out an electron from the monopositive cation. Hence, M(g)M2++2eM(g)M++eM+M2++e.

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