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Question

Consider the following chemical reaction:
CHCH(2) CO,HCl,AlCl3−−−−−−−−−−−−−−−(1) Red hot Fe tube,873 KProduct
The number of sp2 hybridized carbon atom(s) present in the product is _____.

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Solution

When acetylene is passed through red hot Fe tube at 873 K, benzene is formed.
Benzene reacts with CO+HCl in presence of a Lewis acid to formed benzaldehyde. This reaction is known as Gattermann Koch reaction.

Benzaldehyde has 7 carbon atoms and all are sp2 hybridized.

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