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Potassium Permanganate

Consider the ...

Question

Consider the following chemical reaction : ${F e}_{3} O_{4} + C O - F e + {C O}_{2} .$ What mass of ${F e}_{3} O_{4}$ is required to obtain $2 k g$ of Fe if the process is $90 %$ efficient?

2.76

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2.48

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3.05

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2.22

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Solution

The correct option is C $3.05$
$F e_{3} O_{4} + 4 C O ⟶ 3 F e + 4 C O_{2}$
Molecular mass of $F e_{3} O_{4} = 3 \times 57 + 64 = 235$ $g m$
Mass of $3$ $m o l e$ of $F e = 171$ $g m$
$⟹ 235$ $g m$ $F e_{3} O_{4} ⟶ 171$ $g m$ $F e$
$(x)$ $g m ⟶ 2000$ $g m$ $F e$
$⟹ x = \frac{2000 \times 235}{171} = 2748.5$ $g$
As the process is $90 %$ efficient
Amount of $F e_{3} O_{4}$ required $= \frac{100}{90} \times 2748.5$ $g m = 3.05$ $k g$

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