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Limiting Reagent or Reactant

Consider the ...

Question

Consider the following combustion reaction:
$C_{3} H_{8} (g) + 5 O_{2} (g) \to 3 C O_{2} (g) + 4 H_{2} O (g)$
At STP (atm), when 64.4 L of propane is reacted with 87.0 L of oxygen gas, volume of the $C O_{2}$ gas produced is:

105 L of

C O_{2}

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258 L of

C O_{2}

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39.2 L of

C O_{2}

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52.2 L of

C O_{2}

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Solution

The correct option is D 52.2 L of $C O_{2}$
1 mole of propane requires 5 moles of oxygen
22.4 L of propane requires $(5 \times 22.4)$ L of oxygen
64.4 L of propane will require $\frac{5 \times 22.4}{22.4} \times 64.4 = 322$ L of oxygen
Therefore, oxygen is the limiting reagent.
5 moles of oxygen produce 3 moles of $C O_{2}$
$(5 \times 22.4)$ L of oxygen produces $(3 \times 22.4)$ L of $C O_{2}$
So, 87 L of oxygen will produce $\frac{3 \times 22.4}{5 \times 22.4} \times 87$ = 52.2 L of $C O_{2}$

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Similar questions

Q. Consider the following combustion reaction:

C_{3} H_{8} (g) + 5 O_{2} (g) \to 3 C O_{2} (g) + 4 H_{2} O (g)

At STP (atm), when 64.4 L of propane is reacted with 87.0 L of oxygen gas, volume of the

C O_{2}

gas produced is:

Q. Propane and oxygen react according to the equation:

C_{3} H_{8} (g) + 5 O_{2} (g) \to 3 C O_{2} (g) + 4 H_{2} O (g)

If two moles of

C_{3} H_{8} (g)

is used in the above reaction then determine how many grams of water will produce after the complete combustion?

When 22.4 L of C $_{4}$ H $_{8}$ at STP is burnt completely, 89.6 L of CO $_{2}$ gas at STP and 72 g of water are produced. The volume of the oxygen gas at STP consumed in the reaction is closest to :

$C_{3} H_{8} (g) + 5 O_{2} (g) \to 3 C O_{2} (g) + 4 H_{2} O (l)$

The combustion of propane,

C_{3} H_{8} (g)

, proceeds according to the equation above. In the complete combustion of 44.0 grams of propane, determine how many grams of water will be formed.

Q. Calculate the volume of

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Limiting Reagent or Reactant

Standard XI Chemistry

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Consider the following combustion reaction: C3H8(g)+5O2(g)→3CO2(g)+4H2O(g) At STP (atm), when 64.4 L of propane is reacted with 87.0 L of oxygen gas, volume of the CO2 gas produced is:

Consider the following combustion reaction:
$C_{3} H_{8} (g) + 5 O_{2} (g) \to 3 C O_{2} (g) + 4 H_{2} O (g)$
At STP (atm), when 64.4 L of propane is reacted with 87.0 L of oxygen gas, volume of the $C O_{2}$ gas produced is: