Question

Consider the following complexes.

(i) $K_{2}PtC{l}_6$ (ii) $PtC{l}_4\cdot 2N{H}_3$

(iii) $PtC{l}_4\cdot 3N{H}_3$ (iv) $PtC{l}_4\cdot 5N{H}_3$

Their electrical conductances in aqueous solutions are:

• A. $256,0,97,404$
• B. $404,0,97,256$
• C. $256,97,0,404$
• D. $404,97,256,0$

Answer 1

The correct option is A $256,0,97,404$

Greater the number of ions, greater the conductance.

A) $K_2\left[PtC{l}_6\right]\rightleftharpoons \underset{threeion}{\underset{}{2K^{+}+[PtC{l}_6{]}^{2-}}}$

B) $PtC{l}_4\cdot 2N{H}_3\rightleftharpoons \left[Pt\right(N{H}_3{)}_{2}C{l}_4]\to$ no ion (least).

C) $\left[Pt\right(N{H}_3{)}_{3}C{l}_3]Cl\rightleftharpoons$ two ions.

D) $\left[Pt\right(N{H}_3{)}_{5}Cl]C{l}_3\rightleftharpoons$ four ions (maximum)

Hence, (A) is the answer.