CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
240
You visited us 240 times! Enjoying our articles? Unlock Full Access!
Question

Consider the following complexes:
  1. V(CO)6
  2. Fe(CO)5
  3. Cr(CO)6
  4. [Mn(CO)6]
  5. [PtCl6]2
Among the given complexes, number of complexes which have 18 e in their valence shell is/are:

Open in App
Solution

V atom in V(CO)6 contains 17 valence electrons. 12 electrons are from 6 CO ligands and 7 electrons are from V. Hence, the complex does not obey 18-electron rule.
Fe(CO)5=8+5×2=18e
Cr(CO)6=6+6×2=18e
[Mn(CO)6]7+(6×2)=19e[Pt(Cl)6]26+(6×2)=18e

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Denticity of Ligands
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon