Consider the following compounds.
$C l_{3} C - C O O H$ $B r_{3} C - C O O H$ $I_{3} C - C O O H$
(I) (II) (III)
The decreasing order of decarboxylation is:

I > I I > I I I

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I I I > I I > I

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I I I > I > I I

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I I > I > I I I

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Solution

The correct option is B $I > I I > I I I$
$- I$ effect of $C l > B r > I$ .

The decreasing order of stabilities of carbanion is:

$C l_{3} C^{-} > B r_{3} C^{-} > I_{3} C^{-}$

Hence, the decreasing order of ease of decarboxylation is $I > I I > I I I$ .

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Similar questions

Order of decreasing acidity of the following is

(I) HCOOH

(II) ${C H}_{3} C O O H$

(III) ${C l}_{2} C H C O O H$

(IV) ${C F}_{3} C O O H$

(i) H C O O H (i i) P h - C O O H (i i i) P h - O H

(i v) C H_{3} C O O H

C H \equiv C - C O O H; C H_{2} = C H - C O O H; C H_{3} C H_{2} C O O H

- S O_{3} H

Order of decreasing acidity of

$(i) H C O O H (i i) C H_{3} C O O H (i i i) C l_{2} C H C O O H (i v) C F_{3} C O O H i s$

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