Consider the following data: ΔHfo(N2H4,l)=50kJ/mol,ΔHfo(NH3,g)=−46kJ/mol B.E.(N−H)=393kJ/mol,B.E.(H−H)=436kJ/mol ΔvapH(N2H4,l)=18kJ/mol The N−N bond energy in N2H4 is:
A
226kJ/mol
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
154kJ/mol
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
190kJ/mol
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
none of the above
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is D190kJ/mol The balanced chemical reactions are given below. (a) N2(g)+2H2(g)⇌N2H4(l);ΔHf=50kJ/mol
(b) N2H4(l)⇌N2H4(g);ΔH−Vap=18kJ/mol
(c) 12N2(g)+32H2(g)⇌NH3(g);ΔHf=−46kJ/mol
(i) For the reaction c, ΔH=12(ΔH(N≡N)+3ΔH(H2)−6ΔH(N−H)) −46×2=ΔH(N≡N)+3(436)−6(393) ΔH(N≡N)=958kJ/mol
(ii) Add reactions a and b. N2(g)+2H2(g)⇌N2H4(g) ΔHf=50+18=68kJ/mol ΔH=ΔH(N≡N)+2ΔH(H−H)−(ΔH(N−N)+4ΔH(N−H)) 68=958+2(436)−(ΔH(N−N)+4(393)) ΔH(N−N)=958+872−68−1572=190kJ/mol