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Question

Consider the following data:
ΔHfo(N2H4,l)=50kJ/mol,ΔHfo(NH3,g)=46kJ/mol
B.E.(NH)=393kJ/mol,B.E.(HH)=436kJ/mol
ΔvapH(N2H4,l)=18kJ/mol
The NN bond energy in N2H4 is:

A
226 kJ/mol
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B
154 kJ/mol
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C
190 kJ/mol
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D
none of the above
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Solution

The correct option is D 190 kJ/mol
The balanced chemical reactions are given below.
(a) N2(g)+2H2(g)N2H4(l);ΔHf=50kJ/mol

(b) N2H4(l)N2H4(g);ΔHVap=18kJ/mol

(c) 12N2(g)+32H2(g)NH3(g);ΔHf=46kJ/mol

(i) For the reaction c, ΔH=12(ΔH(NN)+3ΔH(H2)6ΔH(NH))
46×2=ΔH(NN)+3(436)6(393)
ΔH(NN)=958kJ/mol

(ii) Add reactions a and b.
N2(g)+2H2(g)N2H4(g)
ΔHf=50+18=68kJ/mol
ΔH=ΔH(NN)+2ΔH(HH)(ΔH(NN)+4ΔH(NH))
68=958+2(436)(ΔH(NN)+4(393))
ΔH(NN)=958+872681572=190kJ/mol

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