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Standard XII

Chemistry

Stoichiometric Calculations

Consider the ...

Question

Consider the following data:
Element Atomic mass
A 12.01
B 35.5
A and B combine to form new substance X. If 4 moles of B combine with 1 mole of A to give 1 mole of X, then weight of one mole of X is:

154 g

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74 g

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47.5 g

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166 g

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Solution

The correct option is A 154 g
As given :
A and B combine to form new substance X where 4 moles of B combine with 1 mole of A to give 1 mole of X.
$A + 4 B \to X$
Hence molar mass of $X = 12.01 + 4 \times 35.5 = 154 g m o l^{- 1}$ ]

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Similar questions

Q. Consider the following data:

Element	Atomic weight
A	12.01
B	35.5

A and B combine to form a new substance X. If 4 moles of B combine with 1 mole of A to give 1 mole of X, then the weight of 1 mole of X is:

Q. If

1 \frac{1}{2}

moles of oxygen combine with

A l

to form

A l_{2} O_{3}

, the weight of

A l

used in the reaction is:

(A l = 27)

Q. The elements

A

and

B

combine together to give two compounds

A_{2} B_{3}

and

A B_{2}

. The weight of 0.2 mole of

A_{2} B_{3}

is 26gm. The weight of 0.3 mole of

A B_{2}

is 24 gm. Then the atomic weights of

A

and

B

respectively.

Q. The half mole of oxygen combine with

A l

to form

A l_{2} O_{3}

, the weight of

A l

used in the reaction is:

I

. Experimental data reveals that

1 m o l e

of a metal (

X

) combines with

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of a nonmetallic element (

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Consider the following data: ElementAtomic massA12.01B35.5 A and B combine to form new substance X. If 4 moles of B combine with 1 mole of A to give 1 mole of X, then weight of one mole of X is:

The correct option is A 154 gAs given :A and B combine to form new substance X where 4 moles of B combine with 1 mole of A to give 1 mole of X. A+4B→XHence molar mass of X=12.01+4×35.5=154gmol−1 ]

Consider the following data:
Element Atomic mass
A 12.01
B 35.5
A and B combine to form new substance X. If 4 moles of B combine with 1 mole of A to give 1 mole of X, then weight of one mole of X is:

The correct option is A 154 g
As given :
A and B combine to form new substance X where 4 moles of B combine with 1 mole of A to give 1 mole of X.
$A + 4 B \to X$
Hence molar mass of $X = 12.01 + 4 \times 35.5 = 154 g m o l^{- 1}$ ]