To find the median of the given data set, we first arrange the data points in ascending order, except the unknown
x.
11 |
12 |
13 |
15 |
16––– |
18––– |
20 |
22 |
23 |
x |
As it is an even-numbered data set, median is the mean of two central data points.
As per the current arrangement, the two middle-positioned data points are
16 and
18.
Mean of
16 and
18 is
16+182=17, which is not the median as per the question.
As per the question, the median is
16.5, so we can place the unknown
x just after
16, such that there is a possibility to get the mean of
16 and
x as
16.5.
Hence, the correct arrangement becomes
11 |
12 |
13 |
15 |
16––– |
x–– |
18 |
20 |
22 |
23 |
∴The median of the above data set=16+x2=16.5
⇒16+x2=16.5
⇒16+x2×2=16.5×2
(multiplying
2 both sides)
⇒16+x=33
⇒16+x−16=33−16
(substracting
16 from both sides)
⇒x=17
Hence, the given data set becomes
11 |
12 |
13 |
15 |
16––– |
17––– |
18 |
20 |
22 |
23 |
And, the value of the unknown
x is
17.