Question

Consider the following declaration of a two-dimensional array in C

char a[100][100];

Assuming that the main memory is byte-addressable and that the array is stored starting form memory address 0, the address of a[40][50] is

• A. 5040
• B. 4050
• C. 4040
• D. 5050

Answer 1

The correct option is B 4050

Address of a[40][50] = Base address + 40 $\times$ 100 $\times$ element size + 50 $\times$ element size

= 0 + 4000 $\times$ 1 + 50 $\times$ 1
= 4050

Therefore, option (b) is correct.