Consider the following $E^{o}$ values
$E_{{F e}^{3 +} / {F e}^{2 +}} = + 0.76 V$
$E_{{F e}^{2 +} / {F e}} = - 0.44 V$
$E_{{S n}^{2 +} / {S n}} = - 0.14 V$
Under standard conditions, calculate the EMF for the cell reaction :
$3 {S n}_{(s)} + 2 {F e}^{3 +} (a) \to 2 F e (a q) + 3 {S n}^{2 +} (a q)$

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Solution

Comparing gibb's free energy,
$n F E^{0} = n F E_{1}^{0} + n_{2} F E_{2}^{0}$
$3 E^{0} = 0.76 - 0.88$
$E^{0} = - 0.04 V$
${F e}^{3 +} / F e$
Now, $3 S n + 2 {F e}^{3 +} \to 2 F e + 3 {S n}^{2 +}$
$E_{c e l l} = {E^{0}}_{{F e}^{3 +} / F e} - E_{{S n}^{2 +} / S n}$
$= - 0.04 - (- 0.14)$
$E_{c e l l} = 0.1 V$

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Similar questions

E^{0}

E^{0_{F e 3 + / F e 2 +}} = + 0.77 V

E_{S n^{2 +} / S n}^{0} = - 0.14 V

S n (s)

+ 2 F e^{3 +} (a q) \to 2 F e^{2 +} (a q) + S n^{2 +} (a q)

E^{0}

E_{F e^{3 +} / F e^{2 +}}^{0}

E_{S n^{2 +} / S n}^{0}

S n (s) + 2 F e^{3 +} (a q) \to 2 F e^{2 +} (a q) + S n^{2 +} (a q)

Consider the following $E^{0}$ values:

$E_{F e^{3 +} / F e^{2 +}}^{0} = + 0.77 V$ ; $E_{S n^{2 +} / S n}^{0} = - 0.14 V$

Under standard conditions the EMF for the reaction

$S n_{(s)} + 2 F e {^{3 +}}_{(a q)} \to 2 F e {^{2 +}}_{(a q)} + S n {^{2 +}}_{(a q)}$ is :

E_{F e^{3 +} / F e^{2 +}}^{\circ} = + 0.77 V; E_{S n^{2 +} / S n}^{\circ} = - 0.14 V

S n_{(s)} + 2 F e_{(a q)}^{3 +} \to 2 F e_{(a q)}^{2 +} + S n_{(a q)}^{2 +}

E_{{F e}^{2 +} / F e}^{o} = - 0.44 V E_{{F e}^{3 +} / {F e}^{2 +}}^{o} = 0.77 V

F e + 2 {F e}^{3 +} \to 3 {F e}^{2 +}

E^{o} :

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