Question

Consider the following electric circuit:

If $\text{V}=15\text{V}$, ${\text{V}}_1=5\text{V}$, ${\text{V}}_3=4\text{V}$ and the electric current $\text{I}=2\text{A}$, which of the following is correct?

• A. The electric current through the bulb ${\text{V}}_2$ is $2\text{A}$.
• B. ${\text{V}}_2=24\text{V}$
• C. ${\text{V}}_2=6\text{V}$
• D. The electric current through the bulb ${\text{V}}_2$ is $\frac{2}{3}\text{A}$.

Answer 1

Answer: (A), (C)

${\text{V}}_2=6\text{V}$

The given electric circuit is a series electric circuit, i.e. the bulbs are connected in series with the battery.

In a series electric circuit, the total voltage is equal to the sum of the individual voltages, i.e. $\text{V}={\text{V}}_1+{\text{V}}_2+{\text{V}}_3$
$⟹{\text{V}}_2=\text{V}-({\text{V}}_1+{\text{V}}_3)$
$⟹{\text{V}}_2=15-(5+4)$
$⟹{\text{V}}_2=15-9=6\text{V}$

In a series electric circuit, the current flowing through all the components is same, i.e. the current flowing through the bulb ${\text{V}}_2$ is also going to be $2\text{A}$.