Consider the following equation.
$H_{2} S_{2} O_{7} + H_{2} O \to (A)$
When compound (A) is allowed to react with $P_{2} O_{5}$ , compound (C) is formed. How many $p_{π} - d_{π}$ bonds are present in compound (C).

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Solution

$H_{2} S_{2} O_{7}$ is oleum which upon hydrolysis produces sulphuric acid.
$H_{2} S_{2} O_{7} + H_{2} O \to H_{2} S O_{4} (A)$
$H_{2} S O_{4} (A) P_{2} O_{5} - --- \to - H_{2} O S O_{3} (C)$

Here in the $S O_{3}$ , one $p_{π} - p_{π}$ and two $p_{π} - d_{π}$ bonds are present.

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Similar questions

H_{2} S_{2} O_{7} + H_{2} O \to (A)

P_{2} O_{5}

d_{π} - p_{π}

d π - p π

{C l O_{4}}^{-}

S O_{3}

p π - d π

d_{π} - p_{π}

C l O_{3}^{-}

How many covalent bonds are present in the following compounds?

(i) $C O_{2}$

(ii) $H_{2} O$

(iii) $C H_{4}$

(iv) $N_{2}$

(v) $N H_{3}$

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