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Question

Consider the following equilibrium:

AgCl+2NH3[Ag(NH3)2]++ClSoluble
White ppt. of AgCl appears on adding?

A
NH3
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B
aq.NaBr
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C
aq.HNO3
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D
aq.NH4I
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Solution

The correct option is C aq.HNO3
2HNO3 + [Ag(NH3)2]+ +Cl AgCl+2NH4 +2NO3

When nitric acid is added to amine solution, solution is made acidic and the complex ion dissociates and liberate silver ion to recombine with chloride ion. This is the conformatory test for silver in group 1.

AgCl+2NH3[Ag(NH3)2]++ClSoluble

Dilute nitric acid or hydrochloric acid neutralizes the excess ammonia and the precipitate reappears because the equilibrium is shifted backwards.

Hence,option C is correct.

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