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Characteristics of Equilibrium Constant

Consider the ...

Question

Consider the following equilibrium reaction $N_{2} (g) + 3 H_{2} (g) ⇋ 2 {N H}_{3} (g)$ . What is the unit of the equilibrium expression for this reaction?

L {m o l}^{- 2}

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L^{2} {m o l}^{- 2}

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L^{- 2} {m o l}^{- 2}

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L^{1} {m o l}^{- 1}

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Solution

The correct option is B $L {m o l}^{- 2}$
Units $= {(m o l / l i t r e)}^{Δ n}$
$Δ n = 2 - 4 = - 2$
Units $= {(m o l / l i t r e)}^{- 2}$
$= {l i t}^{2} {m o l}^{- 2}$

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Similar questions

N_{2} (g) + 3 H_{2} (g) ⇌ 2 {N H}_{3} (g)

K_{C} = L^{2} {m o l}^{- 2}

N_{2} (g) + 3 H_{2} (g) ⇌ 2 {N H}_{3} (g)

K_{C} = \frac{{[{N H}_{3}]}^{2}}{[N_{2}] {[H_{2}]}^{3}}

K_{C}

N_{2} (g) + 3 H_{2} (g) ⇋ 2 N H_{3} (g)

L^{2} m o l^{- 2}

3.0 m o l L^{- 1}

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m o l L

^{- 1} H_{2}

0.5 m o l L^{- 1}

N H_{3}

N_{2}

_{2}

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(K_{c})

C (s) + \frac{1}{2} O_{2} (g) \to C O_{2} (g)

N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g), △ H = - 93.6 k J m o l^{- 1} .

H_{2}

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