CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Reaction Quotient

Consider the ...

Question

Consider the following equilibrium reaction2HI(g) H2 (g)12(g)usThe above equilibrium is established by initiallytaking HI(g) only. If at equilibrium 1 mol each of thespecies is present, then the vapour density ofequilibrium mixture and degree of dissociation atequilibrium are respectively (I-127g/mol

Open in App

Solution

Suggest Corrections

thumbs-up

0

Similar questions

Q. Consider a reaction:

S O_{2} C l_{2} (g) ⇌ S O_{2} (g) + C l_{2} (g)

S O_{2} C l_{2} (g)

is present. The vapour density of an equilibrium mixture of this reaction is 45.
The degree of dissociation of

S O_{2} C l_{2} (g)

Q. Consider a reaction:

S O_{2} C l_{2} (g) ⇌ S O_{2} (g) + C l_{2} (g)

S O_{2} C l_{2} (g)

is present. The vapour density of an equilibrium mixture of this reaction is 45.
The degree of dissociation of

S O_{2} C l_{2} (g)

Q. For the equilibrium

N_{2} O_{4} (g) ⇌ 2 N O_{2} (g)

, mark the correct option that shows the correct relationship of the degree of dissociation -

^{'} α^{'}

D / d

D

is vapour density of

N_{2} O_{4}

d

is vapour density of equilibrium mixture.

Q. If in the reaction

N_{2} O_{4} (g) ⇋ 2 N O_{2} (g), α

is the dissociation constant at equilibrium, then the number of moles at equilibrium will be:

Note: Initially there is only 1 mol.

2 N H_{3} (g) \to N_{2} (g) + 3 H_{2} (g)

Above equilibrium is established by taking initially only ammonia gas in the container. Find the degree of dissociation of ammonia gas in 34 g of the mixture if molar mass of the mixture is

\frac{34}{3} g .

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Equilibrium Constants

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Reaction Quotient

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon