Question

Consider the following figure:


The equivalent uniform rainfall depth for the above shown catchment is _______mm.

• A. 74.64

Answer 1

The correct option is A 74.64
$P_{avg}=\frac{30\times 50+\frac{50+60}{2}\times 60+\frac{60+70}{2}\times 100+\frac{70+80}{2}\times 125+\frac{80+90}{2}\times 200+90\times 50}{30+60+100+125+200+50}$
$=\frac{42175}{565}=74.64mm$