Question

# Question 7 Consider the following frequency distribution Class0.56−1112−1718−2324−29Frequency131015811 The upper limit of the median class is (a) 17 (b) 17.5 (c) 18 (d) 18.5

Solution

## ClassFrequencyCumulativefrequency−0.5−5.513135.5−11.5102311.5−17.5153817.5−23.584623.5−29.51157 Given, classes are not continuous, so we make continuous by subtracting 0.5 from lower limit and adding 0.5 to upper limit of each class. Here, N2=572=28.5, which lies in the interval 11.51-17.5. Hence, the upper limit is 17.5Mathematics

Suggest Corrections

0

Similar questions
View More