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Question 7
Consider the following frequency distribution
Class0.5611121718232429Frequency131015811
The upper limit of the median class is
(a) 17
(b) 17.5
(c) 18
(d) 18.5
 


Solution

ClassFrequencyCumulativefrequency0.55.513135.511.5102311.517.5153817.523.584623.529.51157
Given, classes are not continuous, so we make continuous by subtracting 0.5 from lower limit and adding 0.5 to upper limit of each class.
Here, N2=572=28.5, which lies in the interval 11.51-17.5.
Hence, the upper limit is 17.5

Mathematics

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