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Question

Consider the following frequency distribution
Class0−56−1112−1718−2324−29Frequency131015811
The lower limit of the median class is _____.

A

11.5
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B

17.5
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C

18
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D

18.5
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Solution

The correct option is A
11.5
ClassFrequencyCumulativefrequency0.55.513135.511.5102311.517.5153817.523.584623.529.51157
Given, classes are not continuous, so we can make it continuous by subtracting 0.5 from lower limit and adding 0.5 to upper limit of each class.
Here, N2=572=28.5, which lies in the interval 11.5-17.5.
Hence, the lower limit is 11.5

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