Question

Consider the following frequency distribution table:

Which observation has a frequency greater than one-fourth of the total frequency?

Answer 1

Frequency for A = 4
Frequency for B = 2
Frequency for C = 5 + 1 = 6
Frequency for D = 5
Frequency for E = 3

Total frequency = 4 + 2 + 6 + 5 + 3 = 20

One-fourth of total frequency = $\frac{\left(1\right)\left(20\right)}{4}=5$

The only observation with a frequency greater than 5 is C whose frequency is 6.