The correct option is B
3
The total frequency from the table is given by 6 + 12 + X = 18 + X
We know, 18 + X cannot be more than 20.
If we take X = 0, Total frequency is 18
If we take X =1, Total frequency is 18 + 1 = 19.
If we take X =2, Total frequency is 18 +2 = 20.
However if we take X =3, the total frequency becomes 18 +3 = 21, which is greater than 20.
Therefore, for any value of X that is greater than 2, our condition is not satisfied.
Hence, the possible values of X are 0,1,2
Therefore, 3 values of X are possible.