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Question

Consider the following graph.
Graph is plotted for 1 mol of gas at 400 K , find slope of curve.
[Take : R=0.08LatmmolK]
1149776_6f2acf7c40924173b1f6ed880a227032.png

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Solution

PV=nRT
P=RTv n=1
P2=(RT)2×(1v)2
y=mx
m=R2T2

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