Consider the following graph.
Graph is plotted for 1 mol of gas at 400 K , find slope of curve.
[Take : $R = 0.08 \frac{L - a t m}{m o l - K}$ ]

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Solution

$P V = n R T$
$P = \frac{R T}{v}$ $n = 1$
$P^{2} = (R T)^{2} \times {(\frac{1}{v})}^{2}$
$y = m x$
$m = R^{2} T^{2}$

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