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Question

Consider the following hydrocarbons
H3C−CH|CH3−CH3 H3C−CH3|C|CH3−CH3
(I) (II)
CH3CH2CH2−CH3
(III)
The correct order of boiling point is:

A
(III) > (I) > (II)
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B
(I) > (II) > (III)
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C
(I) > (III) > (II)
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D
(II) > (III) > (I)
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Solution

The correct option is A (III) > (I) > (II)
For compounds with same molecular mass, as branching increases the boiling point decreases.

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