Consider the following hypothetical reaction (at 375 K). The standard free energies in kJ/mol are given below each substance in parentheses.What is the value of the Gibbs free energy for the reaction at this temperature? Is the reaction spontaneous?
2A(−20.0)→B(150.0)+C(−350.0)△G∘=?
A
− 220; yes
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B
− 180; no
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C
− 160; yes
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D
+ 180; no
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E
− 160; no
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Solution
The correct option is C− 160; yes ΔGorxn=ΔGoB+ΔGoC−2ΔGoA ΔGorxn=150.0−350.0−2(−20.0) ΔGorxn=−160.0 kJ/mol Since the value of ΔGorxn is negative, the reaction is spontaneous.