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Question

Consider the following ions:
S2O22, S2O23, S2O24, S2O25, S2O26, S2O27, S2O28

If the number of ions having SS or S=S linkage be x and the number of ions having SOS linkage be y, the number of ions having peroxy-linkage be z.
Find the value of (xy+z).

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Solution

The structures are given as:

So, x=5 and y=1(S2O27) and z=1(S2O28).
Therefore, xz+y=52=2.5

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