wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Consider the following ions:
S2O22, S2O23, S2O24, S2O25, S2O26, S2O27, S2O28

If the number of ions having SS or S=S linkage be x and the number of ions having SOS linkage be y, the number of ions having peroxy-linkage be z.
Find the value of (xy+z).

Open in App
Solution

The structures are given as:

So, x=5 and y=1(S2O27) and z=1(S2O28).
Therefore, xz+y=52=2.5

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
VBT and Orbital Overlap
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon