Consider the following list of reagents: Acidified K2Cr2O7, alkaline KMnO4, CuSO4, H2O2, Cl2, O3, FeCl3 and Na2S2O3. The total number of reagents that can oxidise aqueous iodide to iodine is:
A
7
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B
6
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C
5
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D
4
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Solution
The correct option is B6 K2Cr2O7+7H2SO4+6KI→4K2SO4+Cr(SO4)3+3I2+7H2O
2CuSO4+4KI→Cu2I2+I2+2K2SO4
H2O2+2KI→I2+2KOH
Cl2+2KI→2KCl+I2
O3+2KI+H2O→2KOH+I2+O2
2FeCl3+2KI→2FeCl2+I2+2KCl
2KMnO4+KI+H2O→KIO3+2MnO2+2KOH Na2S2O3 reacts with I2 to form iodide.
There are 6 such reactions in which oxidise aqueous iodide is converted into iodine and KMnO4 cannot.