After applying 4 clock pulses, which input sequence(s) for ABC will always generate logic 1 at the output Z. (Assume initially all flip-flops are cleared)
A
111
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B
101
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C
001
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D
110
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Solution
The correct option is D 110 Output, Z=¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯(A+B)[(¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯A+B)C]=1
So for ABC = 101,110,111,001 will always generate output Z=1