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Byju's Answer
Standard XII
Chemistry
Bond Order by MOT
Consider the ...
Question
Consider the following molecules
I
:
O
2
I
I
:
O
2
(
A
s
F
6
)
I
I
I
:
K
O
2
Choose the correct answer.
A
The correct decreasing bond order is
I
>
I
I
I
>
I
I
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B
The correct decreasing order of bond length is
I
I
I
>
I
>
I
I
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C
The bond strength of I is less than that of
I
I
I
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D
Bond dissociation energy is highest in case of
I
I
I
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Solution
The correct option is
C
The correct decreasing order of bond length is
I
I
I
>
I
>
I
I
In
O
2
(
A
s
F
6
)
,
O
+
2
has bond order 2.5.
O
2
has bond order 2.0.
In
K
O
2
,
O
2
−
has bond order 1.5.
So higher the bond order means to lower the bond length,
So, the correct option is
B
.
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Similar questions
Q.
Rank the following bonds of
C
O
2
−
3
in decreasing order of their bond length
Q.
(I)
C
o
(
C
O
)
6
(II)
C
o
(
C
O
)
5
N
H
3
(III)
C
o
(
C
O
)
4
(
N
H
3
)
2
(IV)
C
o
(
C
O
)
3
(
N
H
3
)
3
(V)
C
o
(
C
O
)
2
(
N
H
3
)
4
(VI)
C
o
(
C
O
)
(
N
H
3
)
5
Which statement is correct for these compounds?
Q.
Arrange the following molecules in the decreasing order of bond angle.
(
i
)
N
H
3
(
i
i
)
C
H
4
(
i
i
i
)
B
F
3
(
i
v
)
B
e
C
l
2
Q.
What is correct increasing order of bond lengths of bond indicated as
I
,
I
I
,
I
I
I
,
and
I
V
in the following compounds?
Q.
Which is correct statement?
As the
s
-character of a hybrid orbital decreases
(I) The bond angle decreases
(II) The bond strength increases
(III) The bond length increases
(IV) Size of orbitals increases
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