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Question

Consider the following molecules
I:O2II:O2(AsF6)III:KO2

Choose the correct answer.

A
The correct decreasing bond order is I>III>II
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B
The correct decreasing order of bond length is III>I>II
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C
The bond strength of I is less than that of III
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D
Bond dissociation energy is highest in case of III
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Solution

The correct option is C The correct decreasing order of bond length is III>I>II
In O2(AsF6), O+2 has bond order 2.5.
O2 has bond order 2.0.
In KO2, O2 has bond order 1.5.
So higher the bond order means to lower the bond length,
So, the correct option is B.

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