Consider the following nuclear disintegration- Z AX - Z-2 A-k X - 2 4 He- Then the value of k will be -

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Standard XII

Chemistry

Bohr's Model of a Hydrogen Atom

Consider the ...

Question

Consider the following nuclear disintegration.
$_{Z}^{A} X \to_{Z - 2}^{A + k} X +_{2}^{4} H e$ . Then the value of $k$ will be :

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Solution

The correct option is C $- 4$
Total number of nucleons on Left hand side is $A$ . Total number of nucleons on the Right hand side is $A + k + 4$ . As number of nucleons is conserved in this nuclear reaction, so $k = - 4$ .

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Consider the following radioactive decay.

_{Z}^{A} X^{*} \to_{Z}^{A} X + k

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State giving reasons, whethere the following nuclear disintegrations allowed or not (star indicates an excited state). [2 MARKS]
(a) $_{Z}^{A} X^{*} \to_{Z}^{A} X + γ$
(b) $_{Z}^{A} X \to_{Z - 2}^{A} X +_{2}^{4} H e$

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2 x + 3 y - 4 k z = 24

on the coordinates is 8, then the value of k is ____________.

If z and 1/z are the zeros of the polynominal 4x^2-2x+(k-4),find the value of k.

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Consider the following nuclear disintegration.AZX→A+kZ−2X+42He. Then the value of k will be :

The correct option is C −4Total number of nucleons on Left hand side is A. Total number of nucleons on the Right hand side is A+k+4. As number of nucleons is conserved in this nuclear reaction, so k=−4.

Consider the following nuclear disintegration.
$_{Z}^{A} X \to_{Z - 2}^{A + k} X +_{2}^{4} H e$ . Then the value of $k$ will be :

The correct option is C $- 4$
Total number of nucleons on Left hand side is $A$ . Total number of nucleons on the Right hand side is $A + k + 4$ . As number of nucleons is conserved in this nuclear reaction, so $k = - 4$ .