Question

Consider the following nuclear reaction: $X^{200}\to A^{110}+B^{90}+$ Energy
If the binding energy per nucleon for $X,A$ and $B$ are $7.4MeV$, and $8.2MeV$ and $8.2MeV$ respectively, the energy released will be:

• A. $90MeV$
• B. $110MeV$
• C. $200MeV$
• D. $160MeV$

Answer 1

The correct option is D $160MeV$

Energy released $=$ total binding energy of $A$ and $B$ less total binding energy of $X$.
$=(110\times 8.2+90\times 8.2)-(200\times 7.4)(902+738)-1480$
$=160MeV$.