Question

Consider the following out of $\underset{\left(I\right)}{H_{2}S{O}_4}\underset{\left(II\right)}{,H_2{S}_2{O}_8,}\underset{III}{H_{2}S{O}_5},\underset{IV}{H_2{S}_2{O}_3}$ and $\underset{\left(V\right)}{H_2{S}_2{O}_7}$
Choose the correct option.

• A. Oxidation number of Sulphur is $+6$ in all except $IV$
• B. Peroxy linkage is in $II$ and $III$
• C. Both statements are correct
• D. None of the above is correct

Answer 1

Answer: (B)

Peroxy linkage is in $II$ and $III$

The oxidation state of $S$ in $H_2{SO}_4$ is +6

Because

$x+2-8=0$

$x=6$

The oxidation state of $S$ in $H_2{S_{2}O}_8$ is +7

The oxidation state of $S$ in $H_2{SO}_5$ is +8

The oxidation state of $S$ in $H_2{S_{2}O}_3$ is +2

The oxidation state of $S$ in $H_2{S_{2}O}_7$ is +6

Peroxy linkage is the covalent $O-O$ bond.it is found in $H_2{S}_2{O}_8$ & $H_{2}S{O}_5$