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Standard XII

Chemistry

Nature of Oxides

Consider the ...

Question

Consider the following oxides:
1. $O F_{2}$
2. $C l_{2} O$
3. $B r_{2} O$
The correct sequence of XOX bond angle is:
(Where, X=F, Cl, Br)

1 > 2 > 3

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3 > 2 > 1

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2 > 1 > 3

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1 > 3 > 2

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Solution

The correct option is B 3 > 2 > 1
The above compounds are the dihalogen oxides as the size of the Halogen atom increases the $X O X$ bond of the dihalogen oxide increases.
So the correct order of bond lengths of given dihalogen oxides is $B r_{2} O > C l_{2} O > O F_{2}$ .
So the correct order is $3 > 2 > 1$ .
Hence option B is correct.

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Similar questions

Q. The bond angle in

O F_{2}

out of

O F_{2}, C l_{2} O, B r_{2} O

is minimum. It is because in case of

O F_{2}

Q. Consider the following statements.
I. In

S i M e_{2} C l_{2}

∠ C l - S i - C l

is smaller than

∠ M e - S i - M e

.
II.

∠ M e - O - M e

M e_{2} O

is smaller than

∠ F - O - F

F_{2} O

.
III.

C - C l

bond length of

C H_{3} C l

is shorter than

C - C l

bond length of

C F_{3} C l

.
IV.

C - F

bond length of

C H_{3} F

is greater than

C - F

bond length of

C H_{2} F_{2}

Q. The correct order of increasing

X - O - X

bond angle is

(X = H, F or C l)

Q. Match list - I and list - II.
List I List II
A.

O F_{2}

1. Oxidation state of

- 1

for halogen
B.

C l_{2} O

2. Oxidation state of

+ 1

for halogen
C.

C l O_{2}

3. Oxidizing agent
D.

C l_{2} O_{6}

4. Gives oxygen with

N a O H

Q. Find the angle between the following pairs of lines:
(i)

\frac{x + 4}{3} = \frac{y - 1}{5} = \frac{z + 3}{4} and \frac{x + 1}{1} = \frac{y - 4}{1} = \frac{z - 5}{2}

(ii)

\frac{x - 1}{2} = \frac{y - 2}{3} = \frac{z - 3}{- 3} and \frac{x + 3}{- 1} = \frac{y - 5}{8} = \frac{z - 1}{4}

(iii)

\frac{5 - x}{- 2} = \frac{y + 3}{1} = \frac{1 - z}{3} and \frac{x}{3} = \frac{1 - y}{- 2} = \frac{z + 5}{- 1}

(iv)

\frac{x - 2}{3} = \frac{y + 3}{- 2}, z = 5 and \frac{x + 1}{1} = \frac{2 y - 3}{3} = \frac{z - 5}{2}

(v)

\frac{x - 5}{1} = \frac{2 y + 6}{- 2} = \frac{z - 3}{1} and \frac{x - 2}{3} = \frac{y + 1}{4} = \frac{z - 6}{5}

(vi)

\frac{- x + 2}{- 2} = \frac{y - 1}{7} = \frac{z + 3}{- 3} and \frac{x + 2}{- 1} = \frac{2 y - 8}{4} = \frac{z - 5}{4}

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Consider the following oxides:1. OF22. Cl2O3. Br2OThe correct sequence of XOX bond angle is:(Where, X=F, Cl, Br)

Consider the following oxides:
1. $O F_{2}$
2. $C l_{2} O$
3. $B r_{2} O$
The correct sequence of XOX bond angle is:
(Where, X=F, Cl, Br)