wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Consider the following partial differential equaiton
32ϕx2+B2ϕxy+32ϕy2+4ϕ=0
For the equation to be classified as parabolic, the value of B2 must be
  1. 36

Open in App
Solution

The correct option is A 36
32ϕx2+B2ϕxy+3ϕy2+4ϕ=0
Compare A2ϕx2+B2ϕxy+Cϕy2+Dϕ=0
A=3,B=?;C=3
Equation to be parabolic
B24AC=0
B24×3×3=0
B2=36

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Reflection of Sound Waves
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon