Question

Consider the following processes.

	$\Delta H\left(kJ/mol\right)$
$1/2A\to B$	+150
$3B\to 2C+D$	-125
$E+A\to 2D$	+350

For $B+D\to E+2C,\Delta H$ will be:

• A. 325 kJ/mol
• B. 525 kJ/mol
• C. -175 kJ.mol
• D. -325 kJ/mol

Answer 1

The correct option is C -175 kJ.mol

$2\left(i\right)-\left(iii\right)+\left(ii\right)$
$\Delta H=2\left(150\right)-350-125$
$=-175kJ/mol$