Consider the following reaction - 2N2O4- 4NO2If -d-N2O4-dt - k and d-NO2-dt - k- then-

The correct option is B k' = 2k 2N_2O_4⇌ 4NO_2 Rate = 12d[N_2O_4]dt = + 14d[NO_2]dt = 12 k= 14 k' or k' = 2k .Hence, the correct option i ...

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Consider the ...

Question

Consider the following reaction :

$2 N_{2} O_{4} ⇌ 4 N O_{2}$

If $- \frac{d [N_{2} O_{4}]}{d t} = k$ and $\frac{d [N O_{2}]}{d t} = k^{'}$ then:

2 k^{'} = k

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k^{'} = 2 k

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k^{'} = k

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k = \frac{1}{4} k^{'}

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2 N_{2} O_{5} \to 4 N O_{2} + O_{2}

\frac{- d [N_{2} O_{5}]}{d t} = k [N_{2} O_{5}]

\frac{d [N O_{2}]}{d t} = k^{^{'}} [N_{2} O_{5}]

\frac{d [O_{2}]}{d t} = k^{''} [N_{2} O_{5}]

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2 N_{2} O_{5} \to 4 N O_{2} + O_{2}

\frac{- d [N_{2} O_{5}]}{d t} = k [N_{2} O_{5}]

\frac{d [N O_{2}]}{d t} = k^{'} [N_{2} O_{5}]

\frac{d [O_{2}]}{d t} = k^{''} [N_{2} O_{5}]

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2 N_{2} O_{5} \to 4 N O_{2} + O_{2}

- \frac{d [N_{2} O_{5}]}{d t} = k [N_{2} O_{5}]

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N_{2} O_{5} \to 2 N O_{2} + \frac{1}{2} O_{2}

- \frac{d [N_{2} O_{5}]}{d t} = K^{'} [N_{2} O_{5}]

\frac{d [N O_{2}]}{d t} = K^{''} [N_{2} O_{5}]

\frac{d [O_{2}]}{d t} = K^{'''} [N_{2} O_{5}]

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2 N_{2} O_{5} ⟶ 4 N O_{2} + O_{2}

\frac{- d [N_{2} O_{5}]}{d t} = k [N_{2} O_{5}]

\frac{d [N O_{2}]}{d t} = k^{'} [N_{2} O_{5}]

\frac{d [O_{2}]}{d t} = k^{''} [N_{2} O_{5}]

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