Consider the following reaction:

$2 S O_{2} (g) + O_{2} (g) ⇋ 2 S O_{3} (g) + h e a t$

What will happen if the temperature of the reacting system is decreased?

More amount of sulphur trioxide will be formed.

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Equilibrium will shift to the back.

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No change

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Less amount of sulphur dioxide will be formed.

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Solution

The correct option is A More amount of sulphur trioxide will be formed.
When the temperature of the reaction is increased, then, according to Le Chatelier's principle the equilibrium system will try to readjust itself to counteract this effect. If we increase the temperature then the system will try to reduce it. Therefore, an endothermic reaction will occur favoring a forward reaction. As a result, sulphur trioxide will be formed from sulphur dioxide and oxygen.

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