Question

Consider the following reaction.
$CaC{O}_3$ + $H_{2}O$ + $C{O}_2$ $\to$ $Ca(HC{O}_3{)}_2$

$\begin{array}{cc}\text{Element}& \text{Number of atoms present}\end{array}$
$\begin{array}{ccc}& \text{Reactant side}& \text{Product side}\\ \text{Calcium}& \text{1}& \text{1}\\ \text{Carbon}& \text{2}& \text{Y}\\ \text{Oxygen}& \text{X}& \text{6}\\ \text{Hydrogen}& \text{2}& \text{2}\end{array}$
The value of $X+Y$ is ___.

.

• A. 3
• B. 6
• C. 4
• D. 3

Answer 1

The correct option is A

3

The given chemical equation is:

$CaC{O}_3$ + $H_{2}O$ + $C{O}_2$ $\to$ $Ca(HC{O}_3{)}_2$

$\begin{array}{cc}\text{Element}& \text{Number of atoms present}\end{array}$
$\begin{array}{ccc}& \text{Reactant side}& \text{Product side}\\ \text{Calcium}& \text{1}& \text{1}\\ \text{Carbon}& \text{2}& \text{(Y = 2)}\\ \text{Oxygen}& \text{(X = 6)}& \text{6}\\ \text{Hydrogen}& \text{2}& \text{2}\end{array}$
Thus, the value of $X+Y=6+2=8.$