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Question

Consider the following reaction.
CaCO3+H2O+CO2Ca(HCO3)2

Element Number of atoms present
Reactant sideProduct sideCalcium11Carbon2YOxygenX6Hydrogen22
Recognise X and Y. The value of X+Y is___.

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Solution

From the equation: CaCO3+H2O+CO2Ca(HCO3)2

Element Number of atoms present
Reactant sideProduct sideCalcium11Carbon2(Y=2)Oxygen(X=6)6Hydrogen22
Thus, the value of X+Y=6+2=8


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