wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Consider the following reaction.
CaCO3+H2O+CO2Ca(HCO3)2

ElementNumber of atoms present
Reactant sideProduct sideCalcium11Carbon2YOxygenX6Hydrogen22
Recognise X and Y. The value of X+Y is___..

Open in App
Solution

From the equation: CaCO3 + H2O + CO2 Ca(HCO3)2

ElementNumber of atoms present
Reactant sideProduct sideCalcium11Carbon2(Y = 2)Oxygen(X = 6)6Hydrogen22
Thus, the value of X+Y=6+2=8


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Introduction
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon