Question

Consider the following reaction $C{H}_3-\stackrel{\stackrel{C{H}_3}{|}}{\underset{\underset{Br}{|}}{C}}-C{H}_{2}C{H}_3\stackrel{Alc.KOH}{⟶}$

which of the following alkene will be the major product?

• A. I
• B. II
• C. both will be formed in equal amount
• D. None of the above

Answer 1

The correct option is A I

Dehydrohalogenation involves removal of (elimination of) a hydrogen halide by abstracting $\beta -H$ from a alkyl halide in presence of base (alc. KOH) to form alkenes.
Saytzeff product will be major product i.e. product (I). Hence correct option is (a).