Consider the following reaction involved in the preparation of teflon polymer -CF2 - CF2n- XeF6 - -CH2-CH2n- -CF2 - CF2-n HG - XeF4-Determine the moles of XeF6 required for preparation of 100 g Teflon-

1 repeating unit of teflon have molecular weight = 100 gso, no. of moles of teflon = 100100 = 1for, preparation of 1 mole of repeating unit of teflon we r ...

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Standard X

Chemistry

Mole Concept

Consider the ...

Question

Consider the following reaction involved in the preparation of teflon polymer $- (C F_{2} - C F_{2})_{n} -$
$X e F_{6} + - (C H_{2} - C H_{2})_{n} \to - (C F_{2} - C F_{2}) -_{n} H G + X e F_{4}$ .
Determine the moles of $X e F_{6}$ required for preparation of $100 g$ Teflon.

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Solution

1 repeating unit of teflon have molecular weight = 100 g
so, no. of moles of teflon = $\frac{100}{100}$ = 1

for, preparation of 1 mole of repeating unit of teflon we require 1 mole of $X e F_{6}$ .

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Consider the following reaction involved in the preparation of teflon polymer −(CF2−CF2)n−XeF6+−(CH2−CH2)n→−(CF2−CF2)−nHG+XeF4.Determine the moles of XeF6 required for preparation of 100 g Teflon.

1 repeating unit of teflon have molecular weight = 100 gso, no. of moles of teflon = 100100 = 1for, preparation of 1 mole of repeating unit of teflon we require 1 mole of XeF6.

Consider the following reaction involved in the preparation of teflon polymer $- (C F_{2} - C F_{2})_{n} -$
$X e F_{6} + - (C H_{2} - C H_{2})_{n} \to - (C F_{2} - C F_{2}) -_{n} H G + X e F_{4}$ .
Determine the moles of $X e F_{6}$ required for preparation of $100 g$ Teflon.

1 repeating unit of teflon have molecular weight = 100 g
so, no. of moles of teflon = $\frac{100}{100}$ = 1

for, preparation of 1 mole of repeating unit of teflon we require 1 mole of $X e F_{6}$ .