Consider the following reaction involved in the preparation of teflon polymer: XeF6+(−CH2−CH2)→(−CF2CF2)+HF+XeF4. Number of moles of XeF6 required for preparation of 100 g teflon is:
A
4
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B
6
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C
8
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D
9
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Solution
The correct option is A4 Balanced chemical equation is as follows: 4nXeF6+(−CH2−CH2−)n→(−CF2−CF2−)n+4nHF+4nXeF4 nteflon=100100n=1n ∴nXeF6required=1n×4n=4 mol. Hence, number of moles of XeF6 required is 4 mol.