Consider the following reaction involved in the preparation of teflon polymer- XeF6-CH2-CH2- -CF2-CF2-HF-XeF4Moles of XeF6 required for preparation of 100 g teflon is-

Reaction: 4XeF_6+( CH_2 CH_2)→ ( CF_2 CF_2 )+4HF+4XeF_4. #160; #160; 4 #160; #160; #160; #160; #160; #160; #160; #160; ...

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Mole Concept

Consider the ...

Question

Consider the following reaction involved in the preparation of teflon polymer.

$X e F_{6} + (- C H_{2} - C H_{2}) \to (- C F_{2} - C F_{2} -) + H F + X e F_{4}$

Moles of $X e F_{6}$ required for preparation of $100$ g teflon is:

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- (C F_{2} - C F_{2})_{n} -

X e F_{6} + - (C H_{2} - C H_{2})_{n} \to - (C F_{2} - C F_{2}) -_{n} H G + X e F_{4}

X e F_{6}

100 g

X e F_{6} + (- C H_{2} - C H_{2}) \to (- C F_{2} C F_{2}) + H F + X e F_{4} .

X e F_{6}

100

(- C F_{2} - C F_{2} -)_{n}

X e F_{2} + (- C H_{2} - C H_{2} -)_{n} \to (- C F_{2} - C F_{2} -)_{n} + H F + X e F_{a^{-}}

X e F_{5}

100 g

300^{\circ} C

C H_{2} O + C_{6} H_{5} O H

F_{2} C = C F_{2}

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