Question

Consider the following reaction taking place in a container,
$2A\left(g\right)\rightleftharpoons 3B\left(g\right)$
On doubling the volume of the container, the equilibrium amount of the product would:

• A. increase
• B. decrease
• C. remain same
• D. Data is insufficient

Answer 1

The correct option is A increase

For the gaseous reaction;
$2A\rightleftharpoons 3B$
when the volume of the container is doubled, the total pressure is reduced to half.
Calculating $\Delta n_g$
$\Delta n_g=3-2=1$
$\Delta n_g>0$
For $\Delta n_g>0$ , when volume is increased , $\frac{n_g}{V}\downarrow$ , the reaction goes where $n_g$ increases.

It increases in the forward direction.
So, more product is formed on doubling the volume.