Consider the following reaction. The product $A$ is:

C_{6} H_{5} C H O

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C_{6} H_{5} O H

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C_{6} H_{5} C O C H_{3}

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C_{6} H_{5} C l

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Solution

The correct option is A $C_{6} H_{5} C H O$
This reaction is resumed reduction in which acid chlorides due reduced to the aldehyde by passing $H_{2}$ in presence of $p d$ catalyst supported over $B a S O_{4}$ .

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Similar questions

C_{2} H_{5} O K + C_{6} H_{5} O H ⇌ C_{2} H_{5} O H + C_{6} H_{5} O K

C_{6} H_{5} O H + C C I_{4} (1) N a O H - ----- \to (2) H^{+}

C_{6} H_{5} C l + C_{2} H_{5} O N a \to

C_{6} H_{5} C H O + H C H O O H^{⊝} - -- \to P r o d u c t

Draw the resonance structures for the following compounds. Show the electron shift using curved-arrow notation.

(a) C₆H₅OH (b) C₆H₅NO₂ (c) CH₃CH = CH – CHO

(d) C₆H₅CHO (e) (f)

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