Question

Consider the following reactions:

$BC{l}_3+LiAl{H}_4\to X+LiCl+AlC{l}_3$

$X+H_{2}O\to H_2+Y\stackrel{Redheat}{\to }Z$
In the above reaction sequence, $X,Y$ and $Z$ are:

• A. $B_2{H}_6,B_2{O}_3,B$
• B. $B_2{H}_6,H_{3}B{O}_3,B_2{O}_3$
• C. $B_2{H}_6,H_{3}B{O}_3,B$
• D. $HB{F}_4,H_{3}B{O}_3,B_2{O}_3$

Answer 1

Answer: (B)

$B_2{H}_6,H_{3}B{O}_3,B_2{O}_3$

Let us consider the complete reaction sequence:

$4BC{l}_3+3LiAl{H}_4\to 2B_2{H}_6+3LiCl+3AlC{l}_3$

$B_2{H}_6+6H_{2}O\to 2B(OH{)}_3+6H_2$

$2B(OH{)}_3\to B_2{O}_3+3H_{2}O$

Hence, in the above reaction sequence, $X,Y$ and $Z$ are $B_2{H}_6,H_{3}B{O}_3$ and $B_2{O}_3$ respectively.