Question

Consider the following reactions:

(i) $C{H}_{3}COOH+X\to C{H}_{3}COO{C}_2{H}_5+H_{2}O$

(ii) $2X+2Na\to 2Y+H_{2}O$
$‘X^{\prime }$ and $‘Y^{\prime }$ respectively are

• A. Ethanol and sodium ethanoate
• B. Ethanol and ethanoic acid
• C. Methanol and sodium methoxide
• D. Ethanol and sodium ethoxide

Answer 1

The correct option is D Ethanol and sodium ethoxide

(i)

The above reaction is called an esterification reaction because ethanoic acid reacts with absolute ethanol in the presence of an acid catalyst to give an ester.

(ii) Ethanol reacts with sodium and forms sodium ethoxide along with the evolution of hydrogen gas.
$2C{H}_{3}C{H}_{2}OH+2Na\to 2C{H}_{3}C{H}_2{O}^{-}N{a}^{+}+H_2\uparrow$
${}^{\prime }{X}^{\prime }$ ${}^{\prime }{Y}^{\prime }$
$‘X^{\prime }$ is ethanol $\left(C{H}_{3}C{H}_{2}OH\right)$ and $‘Y^{\prime }$ is sodium ethoxide $\left(C{H}_{3}C{H}_2{O}^{–}N{a}^{+}\right)$.
Hence, the correct answer is option (d).