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Lead Monoxide

Consider the ...

Question

Consider the following reactions,
(i) ${C O}_{3}^{2 -} + H_{2} O ⇌ {H C O}_{3}^{-} + {O H}^{-}$
(ii) ${C O}_{2} + H_{2} O ⇌ H_{2} {C O}_{3}$
(iii) ${N H}_{3} + H_{2} O ⇌ {N H}_{4} O H$
(iv) $H C l + H_{2} O ⇌ {C l}^{-} + H_{3} O^{+}$
Which of the pairs of reaction proves that water is amphoteric in character?

(i) and (ii)

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(ii) and (iii)

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(iii) and (iv)

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(i) and (iii)

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Solution

The correct option is C (iii) and (iv)
A substance is termed amphoteric if it can show both, the acidic and basic behaviour Water is an amphoteric substance. It has the ability to act as an acid as well as a base. With $N H_{3}$ (which is a base) it acts as an acid.
${N H}_{3} + H_{2} O ⇌ {N H}_{4} O H$
It act as a base with $H_{2} S$ which is bronsted acid.
$H C l + H_{2} O ⇌ {C l}^{-} + H_{3} O^{+}$

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Similar questions

H C l + H_{2} O \to H_{3} O^{+} + C l^{-}

H_{2} O + N_{3} \to O H^{-} + N H_{4}^{-}

H S^{-} + H C l \to C l^{-} + H_{2} S

H S^{-} + N H_{3} \to N H_{4}^{+} + S^{2 -}

H C l + N a O H \to N a C l + H_{2} O

N a C l + H_{2} O \to H C l + N a O H

C a C O_{3} + H C l \to C a C l_{2} + C O_{2} ↑ + H_{2} O

N a + H_{2} O \to N a O H + H_{2} ↑

(N H_{4})_{2} S O_{4} + C a (O H)_{2} \to C a S O_{4} + N H_{3} ↑ + H_{2} O

H g (N O_{3})_{2} \to H g + N O_{2} ↑ + O_{2} ↑

P b_{3} O_{4} + H C l \to P b C l_{2} + C l_{2} ↑ + H_{2} O

H C O_{3}^{-} + H_{2} O ⇌ {C O}_{3}^{2 -} + H_{3} O^{+}

(i) C O_{2} + H_{2} O \to H_{2} C O_{3}

(i i) H_{2} C O_{3} \to H^{+} + H C O_{3}^{-}

(i i i) H_{2} C O_{3} \to H_{2} O + C O_{2}

H_{2} {P O}_{4}^{-}

H_{3} {P O}_{4} + H_{2} O \to H_{3} O^{+} + H_{2} {P O}_{4}^{-}

H_{2} {P O}_{4}^{-} + H_{2} O \to H {P O}_{4}^{2 -} + H_{3} O^{+}

H_{2} {P O}_{4}^{-} + {O H}^{-} \to H_{3} {P O}_{4} + O^{2 -}

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