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Preparation of Carboxylic Acids

Consider the ...

Question

Consider the following reactions-
The correct set of reagents for these reactions is :

R_{1} : H_{2} / L i n d l a r c a t a l y s t, R_{2} : N a / l i q . N H_{3}, R_{3} : (i) O_{3}, (i i) H_{2} O, R_{4} : H_{2} O H_{2} S O_{4}, H g S O_{4}

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R_{1} : H_{2} / L i n d l a r c a t a l y s t, R_{2} : N a / l i q . N H_{3}, R_{3} : H_{2} O, H_{2} S O_{4}, H g S O_{4}, R_{4} : (i) O_{3}, (i i) H_{2} O

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R_{1} : (i) O_{3}, (i i) H_{2} O, R_{2} : H_{2} O H_{2} S O_{4}, H g S O_{4}, R_{3} : N a / l i q . N H_{3}, R_{4} : H_{2} / L i n d l a r c a t a l y s t

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R_{1} : H_{2} O H_{2} S O_{4}, H g S O_{4}, R_{2} : H_{2} / L i n d l a r c a t a l y s t, R_{3} : (i) O_{3}, (i i) H_{2} O, R_{4} : N a / l i q . N H_{3}

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Solution

The correct option is B $R_{1} : H_{2} / L i n d l a r c a t a l y s t, R_{2} : N a / l i q . N H_{3}, R_{3} : H_{2} O, H_{2} S O_{4}, H g S O_{4}, R_{4} : (i) O_{3}, (i i) H_{2} O$
In the first reaction $(R_{1})$ , hydrogen in presence of Lindlar catalyst is used. Carbon carbon tripple bond is selectively reduced to double bond. Syn addition results in cis alkene. In the second reaction $(R_{2})$ , sodium metal in liq ammonia is used. Anti addition results in trans alkene.
The third reaction $(R_{3})$ is the hydration of alkene. 1% mercuric sulphate and dil sulphuric acid are added. The intermediate enol is tautomerized to keto. The reaction is called kucherov reaction. The fourth reaction $(R_{4})$ is the ozonolysis reaction. The reagents are ozone and water. The carbon carbon tripple bond breaks to form moles of carboxylic acid.

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